(5\sqrt5x^3-81\sqrt3y^3) \div(\sqrt5x-3\sqrt3y) =(\A x^2+\B y^2 +\C xy) then (6\A+\B-\sqrt15\C)

SSC CGL Model Paper 17

Question : 74 of 99

Marks: +1, -0

(5√5x^3-81√3y^3)

÷(√5x-3√3y)

=(\A x^2+\B y^2 +\C xy)

then

(6\A+\B-√15\C)

Solution:

(5√5x^3-81√3y^3)/(√5x-3√3y)

=(\A x^2+\B y^2 +\C xy)

⇒5x^2+27y^2+3√15xy

=\A x^2+\B y^2 +\C xy

Compare both side

\A= 5,\B=27,\C=3√15

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