The value of \frac{2+\tan^2\theta+\cot^2\theta}{\sec\theta\cosec\theta}

Correct Answer is : secθcosecθ

SSC CGL Model Paper 17

Question : 73 of 99

Marks: +1, -0

The value of

{2+\tan^2θ+\cot^2θ}/{\secθ\cosecθ}

Solution:

{1+\tan^2θ+1+\cot^2θ}/{\secθ\cosecθ}

={\sec^2θ+\cosec^2θ}/{\secθ\cosecθ}

={1/{\cos^2θ}+1/{\sin^2θ}}/{1/{\cosθ\sinθ}}=1/{\cosθ\sinθ}

=\secθ\cosecθ

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