What is the value of \frac{1-x}{1-x^4}\div{\frac{x^2}{1+x^2}}\timesx(1-x)?

SSC CGL Model Paper 12

Question : 61 of 100

Marks: +1, -0

What is the value of

{1-x}/{1-x^4}÷{{x^2}/{1+x^2}}×x(1-x)?

Solution:

{1-x}/{1-x^4}÷{{x^2}/{1+x^2}}×x(1-x)

={1+x}/{{(1^2)^2-(x^2)^2}}

×{1+x^2}/x^2×x(1-x)

={1+x}/{(1-x^2)(1+x^2)}×{1+x^2}/x(1-x)

=1/x

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