Which value among \sqrt^ 3 {5},\sqrt^ 4 {6}, \sqrt^ 6 {12}, \sqrt^12{276} is the largest ?

SSC CGL 9 Aug 2017 Shift 1 Paper

Question : 51 of 100

Marks: +1, -0

Which value among

√^ 3 {5},√^ 4 {6}, √^ 6 {12}, √^12{276}

is the largest ?

Solution:

√^ 3 {5} =(5)^{1/3}=(5^4)^{1/12}=(625)^{1/12}

√^ 4 {6}=(6)^{1/4}=(6^3)^{1/12}=(216)^{1/12}

√^ 6 {12} =(12)^{1/6}=(12^2)^{1/12}=(144)^{1/12}

√^12{276}=(276)^{1/12}

Hence,

√^ 3 {5}

is the largest number.

Go to Question:

Prev Question

Next Question