SSC CGL 9 Aug 2015 Shift 2 Paper

Question : 148 of 200

Marks: +1, -0

The angle of elevation of a tower from a distance of 100 metre from its foot is 30°. Then the height of the tower is

Solution:

AB = Tower = h metre
From ΔABC,
tan 30° =

{AB}/{BC}

⇒

1/√3

h/{100}

⇒ h =

{100}/√3

metre

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