A person of height 6ft. wants to pluck a fruit which is on a {26}/3 ft. high tree. If the personis standing 8/\sqrt3 ft. away from the base of the tree, then at what angle should he throw a stone so that it hits the fruit ?

SSC CGL 9 Aug 2015 Shift 2 Paper

Question : 147 of 200

Marks: +1, -0

A person of height 6ft. wants to pluck a fruit which is on a

{26}/3

ft. high tree. If the personis standing

8/√3

ft. away from the base of the tree, then at what angle should he throw a stone so that it hits the fruit ?

Solution:

AB = Tree =

{26}/3

feet
BE = CD = 6 feet
AE = AB – BE =

{26}/3

- 6
=

{26-18}/3

8/3

feet
DE = BC =

8/√3

feet
From ΔAED,
tan θ =

{AE}/{ED}

{8/3}/{8/√3}

8/3 × √3/8

1/√3

∴ tan θ = tan 30° ⇒ θ = 30°

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