SSC CGL 9 Aug 2015 Shift 2 Paper

Question : 143 of 200

Marks: +1, -0

If two supplementary angles differ by 44°, then one of the angles is

Solution:

Supplementary angles
= x and 180° – x (let)
According to the question,
180° – x – x = 44°
⇒ 180° – 2x = 44°
⇒ 2x = 180° – 44° = 136°
⇒ x =

{136°}/2

= 68°

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