SSC CGL 31 Aug 2016 Paper

Question : 60 of 100

Marks: +1, -0

In a trapezium ABCD, AB < CD, AB < CD, CD = 6 cm and distance between the parallel sides is 4 cm. If the area of ABCD is 16

cm^2

, then AB is

Solution:

Area of the trapezium ABCD
=

1/2

(AB + CD) × AE
⇒ 16 =

1/2

(AB + ) × 4
⇒ 16 = 2 (AB + 6)
⇒ AB + 6
=

{16}/2

= 8
⇒ AB = 8 - 6 = 2 cm

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