SSC CGL 26 Oct 2014 Shift 2 Paper

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Question : 128 of 200

Marks: +1, -0

If

cos^2

θ –

sin^2

θ =

1/3

, where 0 ≤ θ ≤

π/2

, then the value of

cos^4

θ -

sin^4

θ is

$1/3$
$2/3$
$1/9$
$2/9$

Solution:

cos^2

θ –

sin^2

θ =

1/3

cos^4 θ - sin^4 θ

=

(cos^2 θ + sin^2 θ)

(cos^2 θ - sin^2 θ)

= 1 ×

1/3

=

1/3

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