SSC CGL 26 Oct 2014 Shift 2 Paper

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Question : 127 of 200

Marks: +1, -0

The value of

sin^2

30°

cos^2

45° + 5

tan^2

30° +

3/2 sin^2

90° - 3

cos^2

90° is

3 $7/{24}$
3 $3/{24}$
3 $1/{24}$
3 $5/{24}$

Solution:

sin^2

30°

cos^2

45° + 5

tan^2

30° +

3/2 sin^2

90° - 3

cos^2

90°
=

(1/2)^2 × (1/√2)^3

+ 5 ×

(1/√3)^2 + 3/2

× 1 - 3 × 0
=

1/4 × 1/2

+ 5 ×

1/3+3/2

=

1/8+5/3+3/2

=

{3+40+36}/{24}

=

{79}/{24}

= 3

7/{24}

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