SSC CGL 1 Sep 2016 Paper

Question : 68 of 100

Marks: +1, -0

Two chords AB and PQ of a circle intersect at D inside a circle. If AD = 4 cm., DB = 6 cm., QD = 3 cm., the length of PQ is equal to

Solution:

AD × DB = PD × DQ
⇒ 4 × 6 = PD × 3
⇒ PD =

{4×6}/3

= 8 cm
∴ PQ = PD + DQ
= (8 + 3) cm = 11 cm

Go to Question:

Prev Question

Next Question