If 0.25(4 f-3)=0.05(10 f-9), then f is equal to :

Sainik School Entrance Exam 2018 Solved Paper

Question : 6 of 150

Marks: +1, -0

0.25(4 f-3)=0.05(10 f-9)

, then

f

is equal to :

Solution:

(a)

0.25(4 f-3)=.05(10 f-9)

⇒{25}/{100}(4 f-3)={5}/{100}(10 f-9)

⇒5(4 f-3)=10 f-9

⇒ 20 f-15=10 f-9

⇒ 10 f=6

⇒ f= {6}/{10}=0.6

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