Sainik School Entrance Exam 2018 Solved Paper

Question : 5 of 150

Marks: +1, -0

Two consecutive even numbers are such that half of the larger number exceeds one-forth of the smaller number by 5 . Then the larger number is:

Solution:

(b) Suppose that two consecutive even numbers be

n

and

n+2

ATQ,

{1}/{2}(n+2)= {1}/{4} n+5

⇒

{n+2}/{2}={n+20}/{4}

⇒

4n+8+2 n+40

⇒

2n=32

⇒

n=16

n+2=16+2=18

So, larger number

=18

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