Sainik School Entrance Exam 2018 Solved Paper

Question : 33 of 150

Marks: +1, -0

The parallel sides of a trapezium are in the ratio

4: 3

and the perpendicular distance between them is

12 \cm

. It the Area of the trapezium is

630 \cm^2

, then its shorter of the parallel side is :

Solution:

(a)

Area

= 1/2(3a+4a)×12

⇒

630 = 7a × 6

⇒

a = 630/{7×6}

= 15

3a = 3×15 = 45 \cm

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