RRB RPF RPSF SI and CONS Model Papers 1 with solutions

Question : 33 of 120

Marks: +1, -0

A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in :

Solution:

(a) B’s 1 day work

=1/12

B’s 9 day’s work

=9/12=3/4

Remaining work

=1-3/4=1/4

∴A can finish this work in

{ 20 }/ { 4 }

days

= 5

days

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