RRB Paramedical Staff Nurse Model Paper 2

Distance travelled by boat in upstream $=24\mathit{k}\mathit{m}$
Time taken $=6\mathit{h}$
Thus, speed of boat in upstream $=\frac{24}{6}=4\mathit{k}\mathit{m}\mathit{h}\mathit{r}$
And distance travelled by boat in downstream $=20\mathit{k}\mathit{m}$
Time taken $=4\mathit{h}$
Thus speed of the boat in downstream $=\frac{20}{4}\mathit{k}\mathit{m}\mathit{h}\mathit{r}$
$=5\mathit{k}\mathit{m}/\mathit{h}$
Now, the speed of the boat in still water$=\frac{1}{2}$[Speed of the boat in upstream + speed of the boat in downstream]
$=\frac{1}{2}\left[4+5\right]$
$=\frac{1}{2}\times 9=4.5\mathit{k}\mathit{m}/\mathit{h}$
And speed of the current
$=\frac{1}{2}$[ Speed of the boat in downstream - speed of the boat in upstream]
$=\frac{1}{2}\left[5-4\right]$ $=\frac{1}{2}\times 1=0.5\mathit{k}\mathit{m}/\mathit{g}$