RRB NTPC Prelims Model Paper 5 with solutions

Question : 14 of 100

Marks: +1, -0

A box contains one-rupee, fifty paise and twenty five paise coins. The total number of coins is 378. The ratio of values of the above coins is 13 : 11 : 7. Find the number of fifty paise coins.

Validate

Solution:

(4) Let the value of coins are 13x, 11x and 7x respectively.
Now, No. of 1 rupee coins= 13x
No. of 50 paise coins= 2 × 11x = 22x
No. of 25 paise coins= 4 × 7x = 28x
∴ By question,
13x + 22x + 28x = 378

⇒ 63x = 378 ⇒ x =378/63 = 6

∴No. of 50 paise coins= 22x = 22 × 6 = 132.

Go to Question:

Prev Question

Next Question