RRB NTPC Mains or Stage 2 Model Paper 8 with solutions

Question : 9 of 120

Marks: +1, -0

A and B can finish a work in 10 days while B and C can do it in 18 days. A started the work, worked for 5 days, then B worked for 10 days and the remaining work was finished by C in 15 days. In how many days could C alone have finished the whole work?

30 days
15 days
45 days
24 days

Validate

Solution:

1/10

Work done by (B +C) in 1 day =

1/18

A’s 5 days’ work + B’s 10 days’ work + C’s 15 days’ work = 1
or (A + B)’s 5 days’ work + (B + C)’s 5 days’ work + C’s 10 days’ work = 1
or

5/10+ 5/18+ 10/x= 1

or x = 45 days

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