RRB NTPC Mains or Stage 2 Model Paper 8 with solutions

Question : 8 of 120

Marks: +1, -0

The angle of elevation of a cloud from a point 200 m above a lake is 30° and the angle of depression of its reflection in the lake is 60°. The height of the cloud is

200 m
300 m
400 m
600 m

Validate

Solution:

tan 30° =h/{PM}⇒PM = √3h

tan 60° ={h+ 400}/PM⇒PM ={h+400}/√3

√3h ={h+400}/√3 = 3h – h = 400

⇒2h = 400
⇒So, height of the cloud = 200 + 200
= 400m

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