RRB NTPC Mains or Stage 2 Model Paper 7 with solutions

Question : 32 of 120

Marks: +1, -0

C can do it in 18 days. A started the work, worked for 5 days, then B worked for 10 days and the remaining work was finished by C in 15 days. In how many days could C alone have finished the whole work ?

30 days
15 days
45 days
24 days

Validate

Solution:

1/10

Work done by ((b) +(c)) in 1 day =

1/18

(a)’s 5 days’ work + (b)’s 10 days’ work +(c)’s 15 days’ work = 1
or ((a) + (b))’s 5 days’ work + ((b) + (c))’s 5days’ work
+ (c)’s 10 days’ work = 1
or

5/10+ 5/18+ 10/x= 1or x = 45 days

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