If sin θ — cos θ = 0, then what is the value of the expression: (\sin^6 \theta + \cos^6 \theta )?

RRB NTPC 28 April 2016 Paper

Question : 78 of 100

Marks: +1, -0

If sin θ — cos θ = 0, then what is the value of the expression:

(sin^6 θ + cos^6 θ )?

Solution:

(4)

\sin \θ - \cos \θ =0

⇒ \sin \θ = \cos \θ ⇒ \θ = 45 ^ { \° }

( { 1 } /{ \√{ 2 } } ) ^ { 6 } + ( { 1 }/{ \√ { 2 } } ) ^ { 6 } = { 1 } /{ 8 } + { 1 } /{ 8 } = { 2 / { 8 } = { 1 }/ { 4 }

Go to Question:

Prev Question

Next Question