RRB Junior Engineer Stage 1 Model Papers 9

Question : 11 of 100

Marks: +1, -0

In the following figure. AB be diameter of a circle whose centre is O. If ∠AOE = 150°. ∠DAO = 51° then the measure of ∠CBE is:

6 1/5

Solution:

∠AOE = 150°

∠DAO = 51°

∠EOB = 180° – 150° = 30°

OE = OB

∴ ∠OEB = ∠OBE =150/2=75°

∴

∠CBE = 180° – 75° = 105°

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