RRB Junior Engineer Stage 1 Model Papers 9

Let the side of square = _x
Area of square $={\mathit{x}}^2$
New length of rectangle $=\frac{130}{100}$
New Breadth of rectangle $=\frac{120}{100}\mathit{x}$
Hence, Area of so formed rectangle $=\frac{130}{100}\times \frac{120}{100}\times {\mathit{x}}^2=\frac{156}{100}{\mathit{x}}^2$
Therefore, area of rectangle exceeds the area of square by 56%