If \tan \theta=3/4 and θ is acute, then cosec θ

RRB Junior Engineer Stage 1 Model Papers 8

Question : 16 of 100

Marks: +1, -0

\tan θ=3/4

and θ is acute, then cosec θ

Solution:

\tan θ=3/4

\cot θ=4/3

\cosec^2 θ-\cot^2 θ=1

⇒\cosec θ=√{1+\cot^2 θ}

=√{1+(4/3)^2}=√{1+16/9}=√{25/9}=5/3

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