If tan θ then the value of 2/3 is

\frac{\cot A+\tan B}{\cot B+\tan A}

RRB Junior Engineer Stage 1 Model Papers 7

Question : 4 of 100

Marks: +1, -0

If tan θ then the value of

2/3

Solution:

tan θ + sec θ = 2

(Given) ... (i)

tan^2 θ -sec^2 θ = -1

(Identity)

(tan θ - sec θ) (tan θ + sec θ)=1

tan θ - sec θ ={-1}/2

....(ii)
Adding eqn. (i) and (ii)

2 \tan θ=3/2

\tan θ=3/4

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