RRB Junior Engineer Stage 1 Model Papers 7

Question : 3 of 100

Marks: +1, -0

A train 270 metre long is running at a speed of 36 km per hour, then it will cross a bridge of length 180 metres in :

Solution:

Speed of train = 36 kmph

=(36×5/18)m{/}sec.=10m{/}sec.

\text "Required time"={\text "length of train +Bridge"}/{\text "Speed of train"}

={270+180}/10=45 \seconds

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