RRB Junior Engineer Stage 1 Model Papers 6

Question : 8 of 99

Marks: +1, -0

Two isosceles triangles have equal vertical angles and their areas are in the ratio 9:16. Then the ratio of their corresponding heights is:

Solution:

{ \text "Area of ΔABC"}/{\text "Area of ΔPQR"}={(AD)^2}/{(PS)^2}

{AD}/{PS}=√{9/16}=3/4

Go to Question:

Prev Question

Next Question