If p/q = r/s = t/u = \sqrt5, then what is the value of [(3p^2+4r^2+5t^2)/(3q^2+4s^2+5u^2)]?

RRB Junior Engineer Stage 1 Model Papers 3

Question : 14 of 100

Marks: +1, -0

p/q = r/s = t/u = √5

, then what is the value of

[(3p^2+4r^2+5t^2)/(3q^2+4s^2+5u^2)]

Solution:

Here

p/q=r/s=t/s=√5/1

then,

(3p^2+4r^2+5t^2)/(3q^2+4s^2+5u^2)

={3×(√5)^2+4×(√5)^2+5×(√5)^2}/{3×(1)^2+4×(1)^2+5×(1)^2}

={3×5+4×5+5×5}/{3×1+4×1+5×1}={15+20+25}/{3+4+5}

=60/15=5

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