RRB Junior Engineer Stage 1 Model Papers 3

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Question : 12 of 100

Marks: +1, -0

If

\cos^2θ+\cos^4θ=1

then

{\sinθ}/{\cos^2θ}

is equal to

1
${\cos^2θ}/{\sinθ}$
${\cos^2 45°}/{\sin^2 60°}$
None

Solution:

Given

\sinθ + \sin^2θ = 1

1 – \sin^2θ = \sinθ

Then,

\cos^2θ+\cos^4θ⇒\cos^2θ+(\cos^2θ)^2

⇒(1+\sin^2θ)+(1-\sin^2θ)^2

\sinθ+\sin^2θ=1

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