What is the value of \frac{1+x}{1-x^4} {\div}\frac{x^2}{1+x^2}\timesx(1-x) ?

RRB Junior Engineer Stage 1 Model Papers 1

Question : 20 of 100

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What is the value of

{1+x}/{1-x^4} {÷}{x^2}/{1+x^2}×x(1-x)

Solution:

{1+x}/{1-x^4} {÷}{x^2}/{1+x^2}×x(1-x)

⇒{1+x}/{1-x^4} ×{1+x^2}/{x^2}×x(1-x)

⇒{(1+x)}/{(1)^2-(x^2)^2}×{1+x^2}/x^2×x(1-x)

⇒{(1+x)(1-x)}/{(1-x)(1+x)×x}=1/x

Solve To get Answer.

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