RRB Group D 13-Dec-2018 Shift 2 Solved Paper

Question : 44 of 100

Marks: +1, -0

Starting from point A, Mr X walks 15 km towards the north to reach point B, from where he turns left and walks 10 km to reach point C. Then he turns right, and walks 10 km to reach point D. A nd at last, he turns right and walks 30 km to reach point E. The shortest distance the starting and ending point is

$2√{42}$
$5√{42}$
$5√{41}$
$6√{41}$

Validate

Solution:

The dotted line represent the shortest distance between A and E, which is

√{(25)^2+(20)^2}=√{1025}=5√{41}

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