RRB Assistant Loco Pilot and Technician Model Paper 2 with solutions

Let principal = ₹ 100
SI = $\frac{100\times 10\times 3}{100}=330$
A = $\mathit{P}{\left(1+\frac{\mathit{r}}{100}\right)}^{\mathit{t}}$
= $100{\left(1+\frac{10}{100}\right)}^3$
= 100 × ${\left(\frac{11}{10}\right)}^3$
= $\frac{1331}{10}$
C.I. = A – P = $\frac{1331}{10}$ - 100
= $\frac{331}{10}$ = 33.1
C.I. – S.I. = 33.1 – 30 = 3.1
when diff. is ₹ 3.1 then P = ₹ 100
when diff. is ₹ 31 then P = $\frac{100}{3.1}$ x 31
= $\frac{100}{31}$ x 10 x 31
∴ P = ₹ 1000