If \sin^2 60^\circ+\cos^2(3x-9^\circ)=1, then what is the value of x?

Trigonometry Practice Test 1

Question : 36 of 40

Marks: +1, -0

\sin^2 60°+\cos^2(3x-9°)=1,

then what is the value of x?

Solution:

The given equation can be rewritten as

\cos^2(3x-9°)=1-\sin^2 60°

\cos^2(3x-9°)=\cos^2 60°

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