Trigonometry Practice Test 1

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Question : 35 of 40

Marks: +1, -0

The value of

\cosec^2 θ - 2 + \sin^2 θ

is always:

less than zero
non-negative
zero
1
None of these

Solution:

\cosec^2 θ - 2 + \sin^2 θ

= (\sin θ - \cosec θ) ^2

Hence, it is always non-negative.

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