What is the value of \frac{(20^2-10^2)\div5\times3+10}{1/3\of27+10\div2+1}?

Simplification Test 7

Question : 16 of 40

Marks: +1, -0

What is the value of

\;{(20^2-10^2)÷5×3+10}/{1/3\of27+10÷2+1}

Solution:

\;{(20^2-10^2)÷5×3+10}/{1/3\of27+10÷2+1}

={(400-100)÷5×3+10}/{9+10÷2+1}

={300÷5×3+10}/{9+ 5+1}

={60×3+10}/15=190/15

=38/3=12 2/3

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