What will be the value of \frac{(\sqrt6+1/\sqrt6)^2}{1/2\of18+4}+2/3?

Simplification Test 7

Question : 15 of 40

Marks: +1, -0

What will be the value of

{(√6+1/√6)^2}/{1/2\of18+4}+2/3

Solution:

{(√6+1/√6)^2}/{1/2\of18+4}+2/3

={(√6)^2+(1/√6)^2+2×√6×1/√6}/{9+4}+2/3

={6+1/6+2}/13+2/3

={49/6}/13+2/3

=49/78+2/3=101/78

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