If (20x^ 2 + 7y^ 2 ) : (8y^ 2 + x ^2 ) = 4 : 1, then (x : y) is:

Ratio and Proportion Practice Test 4

Question : 13 of 40

Marks: +1, -0

(20x^ 2 + 7y^ 2 ) : (8y^ 2 + x ^2 ) = 4 : 1

, then (x : y) is:

Solution:

(20x^ 2 + 7y^ 2 ) /(8y^ 2 + x ^2 ) = 4 /1

20x^2+7y^2=4(8y^2+x^2)

16^2=25y^2

x^2/y^2=25/16

x/y=5/4

∴ x : y=5:4

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