Progression Practice Test 1

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Question : 17 of 23

Marks: +1, -0

Find the sum of 125 terms of the AP

1/6,2/7,3/7,.....

1,125
$1025 / 7$
1,025
$1125/ 7$
1,126

Solution:

Let a be the first term and d be the common difference of the given AP. Then

a =1/7

and

d=1/7 .

∴ Required sum

=S_125=125/2[2a+(125-1)d]

=125/2[2×1/7+124×1/7]

=1,125

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