Progression Practice Test 1

Question : 16 of 23

Marks: +1, -0

Divide 64 into four parts in such a way that they are in AP and the product of the first and the 4th part is 72 less than the product of the 2nd and the 3rd parts.

7, 14, 19, 25
7, 13, 19, 25
7, 13, 19, 27
7, 13, 19, 26
None of these

Validate

Solution:

Let the four parts be (a - 3d), (a - d), (a + d) and (a + 3d). The sum of these four parts is 64,
i.e.,

4a = 64 ⇒ a = 16

(a - 3d) (a + 3d) = (a - d) (a + d) - 72

8d^2=72

d = ±3

As a = 16 taking d = 3, the four parts are 7, 13, 19 and 25.

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