Problems based on Numbers Test 4

Question : 28 of 40

Marks: +1, -0

Two numbers are such that their product, their sum and their difference are in the ratio of 6 : 2 : 1 respectively. Their sum is:

Solution:

Let the two numbers be x and y; then

xy : (x + y) : (x - y) = 6 : 2 : 1

Now,

{x-y}/{x+y}=1/2

⇒ 2x - 2y = x + y

⇒ x = 3y,

x + y = 3y + y = 4y

xy = 3y.y = 3y^2

Now,

{x+y}/{xy}=2/6

⇒{4y}/{3y^2}=2/6

∴y=3×4/3=4

Then,

x = 3 × 4 = 12

Hence,

x + y = 12 + 4 = 16

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