Percentage Practice Test 4 with solutions

Question : 2 of 40

Marks: +1, -0

The price of an article was increased by r %. Later the new price was decreased by r %. If the latest price was Re 1, then the original price was:

Solution:

Let the original price be Rs. x; then

{100+r}/100×{100-r}/100×x=1

∴ x = Rs.

( 10000 /{10000 -r^2})

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