Percentage Practice Test 3 with solutions

Question : 33 of 40

Marks: +1, -0

In the expression

xy^2

, the values of both variables x and y are decreased by 20%. By this, the value of the expression is decreased by

Solution:

Decrease in expression

=xy^2-80/100×x(80/100y)^2

=xy^2-64/125xy^2={61xy^2}/125

Hence, decrease percent

={61xy^2}/{125×xy^2}×100=48.8%

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