Mensuration Practice Test 9

Radius of the cylinder = 11.2 cm
Let drop in water level be = h cm
Volume of cylindrical vessel = 19,712 $\mathit{c}{\mathit{m}}^3$
Volume of cylindrical vessel = $\mathit{\pi }{\mathit{r}}^2\mathit{h}$
$\frac{22}{7}\times 11.2\times 11.2\times \mathit{h}$ = 19,712
h = $\frac{19712\times 7}{22\times 11.2\times 11.2}$
h = 50 cm
So, the level of water is dropped by 50 cm.