Mensuration Practice Test 9

Question : 7 of 40

Marks: +1, -0

An iron rod of 1 cm diameter and 8 cm length is drawn into a wire of 18 m length with uniform thickness. The thickness of the wire would be:

Solution:

Volume of the cylinder =

πr^2h

π(1/2)^2 . 8

= 2π
Volume of the wire =

p(r^2)(1800)

= 2π

r^2 1800

= 2

r^2

2/{1800}

r^2

1/{900}

1/{30}

Diameter = thickness of wire =

2/{30}

m =

1/{15}

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