Mensuration Practice Test 9

Let the radius of the circumcircle = R
Radius of the incircle = r
Let the side of a square = 4 cm
Diagonal of a square = $4\sqrt{2}$ cm
R = $\frac{4\sqrt{2}}{2}$ = $2\sqrt{2}$
and r = $\frac{4}{2}$ = 2 cm

Ratio of area of the circle
$\mathit{\pi }{\mathit{R}}^2:\mathit{\pi }{\mathit{r}}^2$
${\mathit{R}}^2:{\mathit{r}}^2$
${\left(2\sqrt{2}\right)}^2:{\left(2\right)}^2$
2 : 1