Logarithms Practice Test 2

Question : 27 of 39

Marks: +1, -0

Find the value of:

\log(a-b)+\log(a^2+ab+b^2)

-\log(a^3-b^3)

Solution:

\log(a-b)+\log(a^2+ab+b^2) -\log(a^3-b^3)

=\log(a-b) (a^2+ab+b^2) -\log(a^3-b^3)

=\log(a^3-b^3)-\log(a^3-b^3)=0

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