Logarithms Practice Test 2

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Question : 26 of 39

Marks: +1, -0

If

\log (0.57) = \ov1. 756

, then the value of

\log57 +\log (0.57)^3+ \log √0.57

is

3.902
2.902
1.902
0.902

Solution:

Here,

\log (0.57) = \ov1. 756

Since,

\log57+\log(0.57)^3+\log√0.57

=1.756+3×\ov1. 756+1/2×\ov 1. 756

=1.756+3(-1+0.756)+1/2(-1+0.756)

=1.756-3+2.268-0.5+0.378

=4.402-3.5=0.902

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