If 1/{\log_a x}+1/{\log_c x}=2/{\log_b x}, then a, b, c are in:

Logarithms Practice Test 2

Question : 21 of 39

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1/{\log_a x}+1/{\log_c x}=2/{\log_b x}

, then a, b, c are in:

Solution:

The given expression

=\log_x a+\log_xc=2\log_xb

⇒\log_xac=\log_xb^2

⇒b^2=ac

Hence, a, b, c are in G.P.

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