Logarithms Practice Test 2

Question : 20 of 39

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Find the value of:

5 \log 2 + 2 \log 5 + 3 \log 1

Solution:

5 \log 2 + 2 \log 5 + 3 \log 1

= \log 2^5 + \log 5^2 + \log 1^3

=\log 32 + \log 25 + \log 1

=\log(32×25×1)=\log(800)

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