Logarithms Practice Test 1

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Question : 14 of 40

Marks: +1, -0

If

2 \log_16 (x^2 + x) - \log_4 (x + 1) = 2

, then x = ?

– 1
16
2
None of these

Solution:

Given equation is equivalent to

\log_4 [(x^2 + x)/(x + 1)] = 2

i.e.,

(x^2 + x)/(x + 1) = 16

⇒{x(x+1)}/{x+1}=16

⇒x=16

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